In an ap sum of first 10 terms is-150
WebThe sum of n terms of AP will be: Sum = a + (a+d) + (a+2d) …… + (l-2d) + (l-d) + l——————– (3) where l= a+ (n-1)d Writing in reverse order, the sum will still remain same. Sum =l+ (l-d)+ (l-2d)..…+ (a+2d)+ (a+d)+a——————- (4) Adding equations 3 and 4, we get 2 × Sum = (a+l)+ [ (a+d)+ (l-d)]………+ [ (l-d)+ (a+d)]+ (l+a)] WebOct 23, 2024 · Let to sum of first 10 terms of an ap =Snthe sum of its next 10 terms of an ap =sn'S₁₀ = -150S₁₀ + S'₁₀ = S₂₀Given :-S'₁₀ = -550Therefore ,S₂₀ = -150 -550 …
In an ap sum of first 10 terms is-150
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WebThe sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235, find the sum of its first twenty terms. Q. WebThe sum of n terms of an AP can be found using one of the following formulas: S n = n/2 (2a+ (n−1)d) S n = n/2 (a 1 +a n) Here, a = a 1 = the first term, d = the common difference, n = number of terms, a n = n th term, S n …
WebApr 8, 2024 · In an AP of 50 terms, the sum of the first 10 terms is 210 and the sum of its last 15 terms is 2565. Find the AP. Questions & Answers CBSE Mathematics Grade 10 Arithmetic Progression Answer In an AP of 50 terms, the sum of the first 10 terms is 210 and the sum of its last 15 terms is 2565. Find the AP. Last updated date: 04th Apr 2024 • WebIn an AP, the sum of first ten terms is -150 and the sum of next ten terms is -550. Find the AP.
WebMar 12, 2024 · Hence the sum of first n terms in an AP is given by the formula: S = n 2 [ 2 a + ( n − 1) d] Learn about Harmonic Progression Sum of N terms of Arithmetic Progression Formula The formula for the sum of n terms in an arithmetic progression is S = n 2 [ 2 a + ( n − 1) d] Where S = sum of the series n = nth term. a = first term d = common difference. WebJul 29, 2024 · In an AP, the sum of first ten terms is -150 and the sum of its next ten terms is -550. Find the A.P.I have provided the easiest solution of above question, ......
WebThe third term of an AP is four times the sixth term and the sum of the first ten terms is 150. Find a) The first term and the common difference b) The least number of terms of the Arithmetic Progression which must be taken for the sum to be negative Expert Solution Want to see the full answer? Check out a sample Q&A here See Solution star_border
Webgiven S10 = a1+a2+...+10 = 150. But we know that: s10 = (a1+a10)*10/2 = 150. ==> a1+a10 = 150/5. ==> a1+a10 = 30. ==> a10 = 30 - a1...... (1) But a10 = a1 + 9*3 = a1 + 27. ==> a10 = … philip locilentoWebMar 27, 2024 · C. I Frequency 10 vicle, me ACB be 0-15 15-30 30-45 45-60 ore than type ogive' for the given data. 18 40 20 60-75 12 29) The sum of the reciprocals of Rehman's ages 3years ago and 5 years from now is Find his present age. philip lockwood artistWebIn an AP, the sum of first ten terms is -150 and the sum of next ten terms is -550. Find the AP. AboutPressCopyrightContact usCreatorsAdvertiseDevelopersTermsPrivacyPolicy &... philip lockwoodWebApr 11, 2024 · Given the sum of the first 10 terms of an AP is -150 and the sum of the next ten terms which means Sum of first 20 terms-Sum of first 10 terms is -530. Let the first … philip lockley cambridgeWebApr 2, 2024 · The median of the distribution given below is 14.4. Find the values of x and y, if the sum of frequency is 20. Find the common difference ' d ' of an AP whose first term is 10 and the sum of the first 14 terms is 1505 . For what value of ' n ', are the nth terms of the APs : 9,7,5,….. and 15,12,9,…. the same? philip lockwood architectWebMar 19, 2024 · Given that sum of the first 10 terms of an A.P. is -150. S10 = -150. And the sum of next 10 terms is -550. So, the sum of first 20 terms = Sum of first 10 terms + sum … truflex pang rubber productsWebOct 20, 2024 · In an AP the sum of first ten terms is -150 and the sum of its next 10 terms is -550. Find the AP. Is this the question you’re looking for? Advertisement Expert-Verified Answer 49 people found it helpful Hey there !! Let a be the first term and d be the common difference of the given AP . S₁₀ = -150. ⇒ Sn = n/2 [ 2a + (n-1)d] philip lofas